5. You have received the following data involving milling of a part by a worker

Question

5. You have received the following data involving milling of a part by a worker in your department. The data are expressed in minutes: Work observation observation observationobservation Average Perf. Ratin 90 50 24 70 57 45 .27 68 53 31 57 26 67 54 .29 48 23 68 56 .30 50 25 68 80 1.2 Your department is scheduled for one 8-hour shift, 5 days per week and workers are given a daily allowance of 72 minutes for personal time and other contingencies. Contractually daily standards are calculated as the normal time divided by I-% allowance. Assembly workers are paid $10.50 per hour. Historically scrap on this part has been averaging 8%. A. Calculate the standard time to produce on part based on the above time study information. B. You are told that the schedule calls for 550 units per day in the foreseeable future. How many workers are needed to achieve this schedule?

Explanation / Answer

Note that allowance factor is not provided. So, we assume that to be equal to 15%. The answers are dependent on this figure. So, get this confired from your instructor.

(A)

Calculate normal time as the sum of (Average time x Perf. Rating factors) -

Normal Time = 0.50 x 0.90 + 0.25 x 1.1 + 0.68 x 0.80 + 0.55 x 1.1 + 0.30 x 1.2 = 2.234 minutes

Standard time = Normal time / (1 - AF) = 2.234 / (1 - 0.15) = 2.628 minutes

(B)

550 units are the required output per day.

But there is an average 8% scrap. So, input to be processed per day = 550/0.92 = 598 units

The time required to process these inputs = 598 x Std. time = 598 x 2.628 = 1572 minutes

Time available to one worker per day = (8 x 60 - 72) = 408 minutes

So, # of workers needed = 1572 / 408 = 3.9 or 4 workers

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