3. (6 points) Suppose two hosts,A and B,are separated by 20,000 kilometers and a

Question

3. (6 points) Suppose two hosts,A and B,are separated by 20,000 kilometers and are connected by a direct link of R 3 Mbps. Suppose the propagation speed over the link is 2.5 x 108 meters/sec. a. Calculate the bandwidth-delay product, R.dprop b. Consider sending a file of 10,000 bits from Host A to Host B. Suppose the file is sent continuously as one large message. What is the maximum number of bits that will be in the link at any given time? c. Provide an interpretation of the bandwidth-delay product.

Explanation / Answer

a. The bandwidth-delay product is given by : R * dprop

dprop = (20000 km * 1000 m/km) / (2.5 * 108 m/sec) = 0.08 sec

Given , R = 3 Mbps

bandwidth-delay product= 3* 106 0.08 = 24*104 bits

b. Bandwidth delay product is the maximum number of bits on the link at a given time.

So, maximum number of bits on the link at any time = 240000 bits

c. Bandwidth delay product is the maximum number of bits on the link at a given time.

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