Hide Submission Folder Information Submission Folder Homework March 23 Instructi

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Hide Submission Folder Information Submission Folder Homework March 23 Instructions Problem : GGC is planning to advertise on TV and Web. There are three stages in both TV and Web ad production- stage 1, stage 2, and stage 3. Each TV ad requires 15 minutes in Stage 1, 20 minutes in stage 2, and 30 minutes in stage 3. On the other hand, each web ad requires 10 minutes in Stage 1, 30 minutes in stage 2, and 15 minutes in stage 3. Since GGC has 10 hours for each one of the stages, what is the maximum number of Ads GGC can make. GGC needs to make sure that there are at least 2 TV ads and at least 2 Web ads in their planning Due Date Mar 26, 2018 12:30 PM Submit Files Submit Cancel

Explanation / Answer

Since each stage have 10 hour for tv advertise. now we have to calculate how many stage we can complete in 10 hours.

10 hours =600 minute

stage 1 = 600/15=40

Stage 2= 600/20=30

Stage 3= 600/30=20

So we can complete stage 3 , 20 times in 10 hours.Since maximum no. of time taken by stage 3.

So we have to plan accordingly to stage 3. And maximum number of tv advertisement will be 20.

Same like tv advertise, we can calculate web advertisement:

Stage 1=600/10=60

Satge 2=600/30=20

Stage 3=600/15=40

Maximum time taken by second stage is 30 mint. And we can complete this stage 20 times in 10 hour. so we have to plan accordingly stage 2. And maximum no. of web advertisement will be 20.

So finally we can make only 20 advertise of tv as well for web in 10 hour.

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