An application is sending a 1 Mbyte file to another machine. The transport layer

Question

An application is sending a 1 Mbyte file to another machine. The transport layer segments the application layer message into 800 byte segments and then adds a 20 byte header to each segment. The network layer adds a 20 byte header also and the data link layer adds another 24 byte header. Each segment is acknowledged with a 10 byte message from the destination application with the same headers added at each layer.

a) How many bytes total are sent over the network in order to transfer the whole file?

b) What percentage of the total is overhead (headers or control messages)?

Explanation / Answer

A)

Length of each segment = 1024/800 =1.28

So there will be total 2 segments one of 800 bytes and another 1024-800 = 224 bytes

first segment size becomes after addition of bytes by defferent layers = 800+ 20 + 20 + 24 = 864 bytes

second segment size becomes after addition of bytes by defferent layers = 224+ 20 + 20 + 24 = 288 bytes

For each segment acknowledgement size = 10 + 20 +20 + 24 =74 bytes

Since thre are 2 segments: 74 *2 =148 bytes

Total bytes sent = 864+288+148 = 1300 bytes

B)percentage of the total is overhead = 100*[(1300-1024)/1024] = 26.95 %

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