I AM SUFFERING SO HARD PLEASE HELP ME MAKE A CODE THAT WILL NOT HAVE AN ERROR CO

Question

• You must have at least 1 of each of the following C datatypes: int, double, and char
• You must have at least 2 null terminated character arrays (strings) that are used for user input.
• Your program will prompt the user for the different data (search for mad libs online for examples) and then display the full mad lib.

Hint and Tips

• doubles must be input using %ld scanf specifier
• You can declare a separate string to act as your story template, e.g.:

   char story_templ[] = "%d fish, %f fish, %s fish, %s fish ";
  

• You may spread a string initialization across multiple lines using the following trick:

   char my_long_string[] = "Twas brillig in the slithy toves,"
                          "Did gyre and gimble in the wabe. "
                          "All mimsy were the borogoves " 
                          "And the momeraths outgrabe. ";

Explanation / Answer

If you're using Python 2, try:

adj1 = raw_input('Type in an adjective: ')

raw_input() is a function that returns the stdin as a string. input(), however, evaluates the code first, meaning it treats it as code. To see what I mean, try this experiment:

smelly = 7

adj1 = str(input('Type in an adjective: ')) # Type in "smelly" without the quotes

print(adj1)

This program will print "7". This is because the interpreter evaluates your text as a variable name which is a reference to the int 7. Then it turns 7 into a string and prints it. But raw_input() doesn't try to evaluate the code first.

In Python 3, input() does what raw_input() did in Python 2. To get Python 2's input() behavior in Python 3, you say eval(input()).

#include <iostream>

using namespace std;

int main(){

bool playagain = true;

while(playagain == true){

char* noun;

char* adjective;

cout << "Enter a noun:";

cin >> noun;

cout << "Enter an adjective:";

cin >> adjective;

cout << "You're not very " << adjective << " if you like to play with " << noun << "s." << endl;

char playagainchar;

cout << "Play again? (y or n): ";

cin >>playagainchar;

if(playagainchar != 'y') playagain = false;

}

}

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