1. In Figure 18-10 ( ), assume that the link between R1 and R2 is upgraded to 17
ID: 3538813 • Letter: 1
Question
1.
In Figure 18-10 (
), assume that the link between R1 and R2 is upgraded to 170 kbs; and the link between the source host and R1 is downgraded to 160 kbs. What is the throughput between the source and destination after these changes? Which link is the bottleneck now?
2.
Rewrite the following IP addresses using binary notation.
a. 220.11.5.88 b. 110.74.16.18
3.
Rewrite the following IP addresses using dotted decimal notation;
a. 10100001 10110000 01110101 00010101
b. 01110110 10001110 11010000 00110001
4.
Find the class of the following classful IP addresses
a. 180.34.54.12 b. 220.34.2.1
5.
Find the class of the following classful IP addresses:
a. 01100000 11110011 10000111 11011101
b. 11101001 11000000 11110000 00011101
6.
Each if the following addresses belongs to a block. Find the first and last address in each block.
a. 14.12.72.8/22 b. 200.107.16.17/16
7.
Show the n leftmost bits of the following network-address/masks that can be used in a forwarding table:
a. 170.40.11.0/24 b. 70.14.0.0/18
8.
An IP datagram has arrived with the following partial information in the header (in hexadecimal)
45000054 00030000 2206 . . . . . .
a. What is the header size?
b. Are there any options in the packet?
c. What is the size of the data?
d. Is the packet fragmented?
e. How many more routers can the packet travel to?
f. What is the protocol number of the payload being carried by the packet?
9.
In an IPv4 datagram, the value of the header-length (HLEN) field is 716.
How many bytes of options have been added to the packet?
10.
Can each of the following be the value of the TTL in a datagram? Explain your answer.
a. 129 b. 0 c. 1 d. 286
11.
Show the unabbreviated colon hex notation for the following IPv6 addresses.
a. An address with 64 0s followed by 32 two-bit %u201C10%u201Ds
b. An address with 32 four-bit %u201C0110%u201Ds
12.
Show the abbreviations for the following addresses:
a. 0000:FFFF:FFFF:FFFF:0000:0000:0000:0000
b. 1234:2346:0000:0000:0000:0000:0000:FFFF
13.
Decompress the following addresses and show the complete unabbreviated IPv6 address
a. ::1111 b. B:A:CC::1234: A
Explanation / Answer
1
160kbps is throughput
link between R2 destination host is bottleneck
2
a) 11011100.00001011.00000101.01011000 b) 01101110.01001010.00010000.00010010
3
a) 161.176.117.21 b) 118.142.208.49
4
a)B b)C
5
a)A b)D
6
a)14.12.75.255 b)200.107.255.255
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