double[] a = new double[5]; for (int i = 0; i<5; i++) a[i] = Math.pow(2, i); pub

Question

double[] a = new double[5];

for (int i = 0; i<5; i++)
    a[i] = Math.pow(2, i);

public class Node
{
    private int info;
    private Node next;

    //Class methods
}

long x(int n)
{
    if (n == 1) return 1;
    else return n * x(n-1);
}

What will be displayed by the System.out.prinltn statement:

System.out.println(x(5)); ?

int RecFunction(int n)
{
    if (n==0) return 0;
    else return RecFunction(n-1) + n;
}

What is the output in the statement:  System.out.println(RecFunction(0)); ?

1. In a binary search tree, the key in the root node is ____ a key in the left subtree. A. smaller than
B. larger than or equal to
C. two times the value of
D. none of the above

Explanation / Answer

here are your answers :
1 ) LARGER THAN.......

2 ) D option i.e using list , linked list , array

3 ) heap

4 ) D option i.e 4.0

5) D option i.e 1

6) mathValues.insert(1) i.e A option

7) C option i.e Linked list

8) Don't Know

9) D option i.e 0

10) A option i.e Sequential Search

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.