1. Store 10 Students 4 Courses Grade points (0-100). The final Rank (1-4) is sto
ID: 3538022 • Letter: 1
Question
1. Store 10 Students 4 Courses Grade points (0-100). The final Rank (1-4) is stored in the 5th Column of the 2-D Array. If the Average of all Courses are >=90 the Rank=1 else if >=80 then Rank=2 else is >=60 then Rank=3 else Rank=4.
Count number of Students got Rank1, Rank2, Rank3, and Rank4.
Find the Rank that majority of students got.
Sample run:
Input:
Enter Student Grades
Student 1 74 53 94 94
Student 2 75 72 55 77
Student 3 68 62 57 83
Student 4 70 71 61 81
Student 5 56 87 81 90
Student 6 63 67 10 84
Student 7 99 85 70 74
Student 8 86 87 68 97
Student 9 95 50 88 93
Student 10 65 64 76 99
Students Rank
74 53 94 94 3
75 72 55 77 3
68 62 57 83 3
70 71 61 81 3
56 87 81 90 3
63 67 10 84 4
99 85 70 74 2
86 87 68 97 2
95 50 88 93 2
65 64 76 99 3
Rank Count
Rank 1 0
Rank 2 3
Rank 3 6
Rank 4 1
The Majority Rank is Rank 3
Explanation / Answer
#include<iostream>
using namespace std;
int main()
{
int student[10][5];
int rank[4]={0};
for(int i=0; i<10; i++)
{
for(int j=0; j<4; j++)
{
cout << " Enter student " << (i+1) << " Grades Exam " <<(j+1) << " : ";
cin >> student[i][j];
}
}
for(int i=0; i<10; i++)
{
double average_grade = static_cast<double> (student[i][0]+student[i][1]+student[i][2]+student[i][3])/4.0;
if(average_grade>=90)
student[i][4]=1;
else if(average_grade>=80)
student[i][4]=2;
else if(average_grade>=60)
student[i][4]=3;
else student[i][4]=4;
}
for(int i=0; i<10; i++)
{
rank[(student[i][4])-1]++;
}
cout << "students " << " " << " Rank " << endl;
for(int i=0; i<10; i++)
{
for(int j=0; j<5; j++)
cout << student[i][j] << " ";
cout << endl;
}
cout << " Rank " << " " << " Count " << endl;
for(int k=0; k<4; k++)
{
cout << "Rank " << (k+1) << " " << rank[k] << endl;
}
int majority =rank[0];
int index = 0;
for(int k=1; k<4; k++)
{
if(rank[k]>majority)
{
majority = rank[k];
index = k;
}
}
cout << " The Majority Rank is Rank " << (index+1) << endl;
system("pause");
return 0;
}
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