Q1. What is the output of the following program? Why? #include main() { typedef

Question

Q1. What is the output of the following program? Why?

#include

main() {

typedef union {

int a;

char b[10];

float c;

}Union;

Union x,y = {100};

x.a = 50;

strcpy(x.b,"hello");

x.c = 21.50;

printf("Union x : %d %s %f n",x.a,x.b,x.c);

printf("Union y : %d %s %f n",y.a,y.b,y.c);

}

Q2. Given the function below. What would happen if the first parameter would be

struct node *list instead of struct node **list? Explain why.

void add_to_list(struct node **list, int n)

{

struct node *new_node;

new_node = malloc(sizeof(struct node));

if (new_node == NULL) {

printf("Error: malloc failed in add_to_list ");

exit(EXIT_FAILURE);

}

new_node->value = n;

new_node->next = *list;

*list = new_node;

}

Explanation / Answer

1)

output:

Union x : 1101791232 21.500000
Union y : 100 d 0.000000

The reason for getting this output is the union members share the common memory location which is allocated to the largest data member.

2)

When **list changed to *list the the lines of code that we have to change is shown below

new_node->value = n;

new_node->next = list;

list = new_node;

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