for i:= step 2*j until 10-j do:=i+1; assume the initial value of j is 1; list th

Question

for i:= step 2*j until 10-j do:=i+1;

assume the initial value of j is 1; list the value of i that are used in the execution of the loop and also which value of i causes the exits from the loop if:

a) it is dynamic loop witha loop parameters changing whenever thier variable are changed

answer: 1,5,exit when i=11

b)it is dynamic loop with loop parameters reevaluated once before each iteration (ie just befor the exist-check)

answer: 1,3,7 exit when i=13

i know the asnwer has u can see, but how do you get them , i never done algol before , can anyone explain what is happening?

thanks,

Explanation / Answer

a) I dont know how to get 1 and 5..

but... 11 is like...
2+2+2+2+2+1 = 11 ( checking for exist)

b) i dont know how to get 1,3,7... but

2+2+2+2+2+2+1 = 13 ( before check for the exist)

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