From Computer Networking: A Top Down Approach (6th Edition): Chapter 7, Review P

Question

From Computer Networking: A Top Down Approach (6th Edition):

Chapter 7, Review Problem 7: Recall the simple model for HTTP streaming shown in Figure 7.3:

Suppose the buffer size is infinite but the server sends bits at variable rate x(t). Specifically, suppose x(t) has the following saw-tooth shape. The rate is initially zero at time t = 0 and linearly climbs to H at time t = T. It then repeats this pattern again and again, as shown in the figure below.

a. What is the server

Explanation / Answer

THIS WILL HELP YOU How to calculate the 'average sending bit rate' for voice / video ? Someone told me that the Wireshark-->Statistics-->protocol hierarchy could do this. So, I went to see the details of it. But there are only 'Mbit/s' and 'End Mbit/s'. I found that the Packet number of 'RTP' is 30392 and the packet number of 'ITU-T Recommendation H.263' is 8979. Then, the 'end packets' of 'RTP' is 21413 (maybe is 30392-8979). So, I guess maybe I should use 'End Mbit/s' of RTP as the 'average sending bit rate' of voice packets and the 'End Mbit/s' of 'ITU-T Recommendation H.263' as the 'average sending bit rate' of video packets. Does these correct ? Well the payload size for the voice is worked out as 64kbps for the sampling rate with 10ms sampling intervals = (64*10)/8 = 80 bytes the default voice payload size is 20ms which = 160 Bytes for G.711 for the H.263 i am struggling to find info on for my assignment aswell ;)

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