Assume an Internet phone application generates packets only during talk spurts.

Question

Assume an Internet phone application generates packets only during talk spurts. During a talk spurt the sender generates bytes at a rate of 1,000 bytes per second, and every 40 msecs the sender gathers bytes into chunks. Assume that RTP is used that will add a header to each chunk. In addition UDP and IP will be used. Suppose all headers (including RTP, UDP and IP) have a total length of h and an IP datagram is emitted every 40 msecs. Find the transmission rate in bits per second for the datagram generated by one side of the application.

Explanation / Answer

Rate Given = 1000Bps

Hence, 40ms will have 1000*40/1000=40 bytes

Add header of length h

Hence every 40ms, a chunk of length (40+h) bytes is emitted

Hence every 1ms, a chunk of length (40+h)/40bytesis emitted

Hence every 1000ms, a chunk of length (40+h)*1000/40 bytes is emitted

Therefore Transmission rate in BytesPerSecond = (40+h)*25

in bits per second = (40+h)*25*8

=200(40+h) bitsPerSecond

Done !!

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