A refrigerator of mass 100kg has coefficient of friction with the floor of mu a

Question

A refrigerator of mass 100kg has coefficient of friction with the floor of mu a = 0.60 and mu k = 0.40. A walkman pushes the refrigerator with horizontal force Fw in the three cases in order of greatest friction force created between the refrigerator and floor.

Explanation / Answer

2) tan (theta) = tan 30 = 0.577 > (u) = 0.25 so motion is not possible Answer is D 3) T = mg sin(theta) = mg sin 30 = 0.5 mg 4) Constant speed implies net force = 0 so we get D-uMg=0 So option E is correct 5) 20 revolutions per minute 20 revolutions - 60 sec For 1 sec 20/60 = 0.333

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.