A refrigerator moves energy from a cold reservoir (the inside of the refrigerato

Question

A refrigerator moves energy from a cold reservoir (the inside of the refrigerator) to a hot reservoir (the kitchen), but some extra energy is required in the form of work done by some outside agent (typically a compressor motor).

Just like the efficiency can be used to tell how 'good' an engine is, the Coefficient of Performance can be used to compare refrigerators. If a refrigerator requires 1.06×104 J of work to remove 4.44×104 J of energy from the inside of a refrigerator, what is the coefficient of performance of the refrigerator?

How much energy is transferred into the hot reservoir (ie., the kitchen)?

Explanation / Answer

Here ,

work required , W = 1.06 *10^4 J

energy removed from cold reserviour , Qc = 4.44 *10^4 J

Now ,

coefficient of performance = Qh/W

coefficient of performance = (Qc + W)/W

coefficient of performance = ( 1.06 *10^4 + 4.44 *10^4 )/(1.06 *10^4 )

coefficient of performance = 5.19

the coefficient of performance of refrigirator is 5.19

energy transferred to hot reservoir = Qc + W

energy transferred to hot reservoir =  1.06 *10^4 + 4.44 *10^4

energy transferred to hot reservoir = 5.5 *10^4 J

the energy transferred to hot reservoir is 5.5 *10^4 J

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