You have a patient in whom you are measuring both airway pressure and esophageal

Question

You have a patient in whom you are measuring both airway pressure and esophageal pressures. After giving a tidal volume of 500 cc's you perform an end-inspiratory hold (no flow- static pressure measurement) and find that the alveolar pressure = 40 cm H2O, and the Pes = 25 cm H2O. The breath started at a PEEP level of 10 cm H2O. Select either correct or incorrect for each of the following statements.

The PTP at the end of inspiration = 15 cm H2O

The compliance of the combined lung and thorax = 16.7 ml/cm H2O

The compliance of the lung = 16.7 ml/cm H2O

Based upon the static pressure-volume curve of the lung, this level of PTP would put his lung volume at TLC

The PTP at the end of inspiration = 15 cm H2O

The compliance of the combined lung and thorax = 16.7 ml/cm H2O

The compliance of the lung = 16.7 ml/cm H2O

Based upon the static pressure-volume curve of the lung, this level of PTP would put his lung volume at TLC

Explanation / Answer

ANSWER :

If we have some measurements of lungs of a patient, such as tidal volume (500 cc's), PEEP or positive end expiratory pressure (10 cm H2O), Alveolar pressure ( 40 cm H2O) and Plateu pressure or Pes (25 cm H2O). Now, we can find Transpulmonary pressure (PTP) and Compliance of lungs using the given values of some pressure differentials of lungs during breathing.

Hence, transpulmonary pressure or PTP of lung would be 15 cm H2O (PTP = Alveolar pressure - Plataeu pressure (Pes) .While compliance of lungs be found by calculations is 33.3 ml/cm H2O (Tidal volume (VT) / Plataeu pressure (Pes) - Positive end-expiratory pressure (PTTP).

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