The action potential on a motor neuron lasts about 1.5 ms. A large motor neuron

Q: The action potential on a motor neuron lasts about 1.5 ms. A large motor neuron

a. Distance = velocity × time = 100 m/s × 1.5×10-3 s = 0.15 m (= 150 mm; we will need this in part b) b. Given that there are nodes of Ranvier every 1 mm apart. Thus, the number of nodes of Ranvier over 150 mm = 150/1 = 150 c. In saltatory conduction, action potential jumps from node to node.

ID: 3475270 • Letter: T

Question

The action potential on a motor neuron lasts about 1.5 ms. A large motor neuron conducts the action potential at about 100 m/s. a. Calculate the distance between the beginning of the action potential and its end during its conduction down the fiber. b. The nodes of Ranvier are interruptions in the myelin sheath in myelinated fibers, and typically they are located about 1 mm apart along the length of the axon. The action potential that you calculated in Part a is spread out over how many nodes of Ranvier? c. In saltatory conduction, what "jumps" from node to node?

Explanation / Answer

a. Distance = velocity × time = 100 m/s × 1.5×10-3 s = 0.15 m (= 150 mm; we will need this in part b)

b. Given that there are nodes of Ranvier every 1 mm apart. Thus, the number of nodes of Ranvier over 150 mm = 150/1 = 150

c. In saltatory conduction, action potential jumps from node to node.

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The action potential on a motor neuron lasts about 1.5 ms. A large motor neuron

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