#4 Award: 10.00 points program claims that it significantly lowers a participant
ID: 3439448 • Letter: #
Question
#4Award: 10.00 points program claims that it significantly lowers a participant's cholesterol level. In order participants is taken. Their cholesterol levels are measured before and A new diet and exercise to test this claim, a sample of 60 after the three-month Foty of the participants recorded lower cholesterol levels at the end of the levels, and 4 participants recorded no change. program. Forty of t nt program, 16 participants recorded higher cholesterol l Use Table 1 a. Specify the competing hypotheses to test the program's claim. Ho: p 20.50: HA: P0.50 Otto: p s 0.50; Ha: p > 0.50 b. Calculate the value of the test statistic. (Negative values should be indicated by a minus sign. Round intermediate calculations to 4 decimal places and your answer to 2 decimal places.) Test statistic c. Calculate the p-value. (Round "test statistic value" to 2 decimal places. Round your answer to4 decimal places.) p-value d. At the 5% significance level, do the data support the program's claim? Yes, since we reject Ho Yes, since we do not reject H- ONo, since we reject Ho No, since we do not reject Ho- rev: 09 05 2013 QC 34262, 11_20 2013_Qc_ 34262 References
Explanation / Answer
Sol)
a) Nullhypothesis: Ho: P=0.50
Alternative hypothesis: H1: P <0.50
level of significance: 5% level of significance
b) Test Statistic:
given n=60 and x=40
proportion of participates lower the cholestrol p=x/n =0.67
Z= (p-P) / Sqrt(PQ/n)
Z= 2.63
c) Pvalue= 0.004269 (using excel)
d) Conclusion: Z cal=2.63 and Z critical value at 5% level is -1.645 (left tail)
Hence we reject the Null hypothesis.
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