Suppose you have a function y = f(x) such that the domain of f(x) is 1 lessthano

Question

Suppose you have a function y = f(x) such that the domain of f(x) is 1 lessthanorequalto x lessthanorequalto 6 and the range of f(x) is -3 lessthanorequalto y lessthanorequalto 5. What is the domain of f(2(x - 3))? 7/2 lessthanorequalto x lessthanorequalto 8 0 lessthanorequalto x lessthanorequalto 5 1 lessthanorequalto x lessthanorequalto 6 7/2 lessthanorequalto x lessthanorequalto 6 3/2 lessthanorequalto x lessthanorequalto 6 What is the range of f(2(x - 3))? -8 lessthanorequalto y lessthanorequalto 0 2 lessthanorequalto y lessthanorequalto 10 -3 lessthanorequalto y lessthanorequalto7 -5 lessthanorequalto y lessthanorequalto 5 -3 lessthanorequalto y lessthanorequalto 5 What is the domain of 2f(x) - 3? 1 lessthanorequalto x lessthanorequalto 6 6 lessthanorequalto x lessthanorequalto 11 -1 lessthanorequalto x lessthanorequalto 6 -4 lessthanorequalto x lessthanorequalto 1 1 lessthanorequalto x lessthanorequalto 8 What is the range of 2f(x) - 3? -9 lessthanor

Explanation / Answer

a)
Domain will remain same 1<=x<=6, So choice 3 is correct answer.
b)
Choice 4 is correct answer, Because graph of f(x) move down by 2 unit .

c)

domain will remain same 1<=x<=6
d)
-3*2-3 <=y <= 5*2-3
-9 <=y <= 7

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