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A population of wild-flowers was scored for flower color. There were 338 blue (B

ID: 34234 • Letter: A

Question

A population of wild-flowers was scored for flower color. There were 338 blue (BB) plants, 1766 violet (BR) plants and 846 red (RR) plants. Remember to keep 4 decimal digits on all frequencies.

Question 1 A population of wild-flowers was scored for flower color. There were 338 blue (BB) plants, 1766 violet (BR) plants and 846 red (RR) plants. Remember to keep 4 decimal digits on all frequencies. What is the frequency of the blue (B) allele? Not yet Points out of 1.00 Answer Flag question Question 2 What is the frequency of the red (R) allele? Not yet Answer Points out of 1.00 Flag question Question 3 A chiquare test was conducted to test the hypothesis that the population genotypic frequencies are consistent with Hardy-Weinberg equilibrium Not yet Fill in the spaces below with the expected numbers for each phenotypic (genotypic) class in the chi-square test. Points out of What is the expected number of blue (BB) plants? 0.75 Answer Flag question Question 4 What is the expected number of violet (BR) plants? Not yet Answer Points out of 0.75 Flag question Question 5 What is the expected number of red(RR) plants? Not yet Answer Points out of 0.75

Explanation / Answer

There were 338 blue (BB) plants, 1766 violet (BR) plants and 846 red (RR) plants. ( 338 + 1766 + 846) = 2950

Frequency of blue allele (B): frequency of BB + 1/2(frequency of violet)

338 / 2950 + 1766/2*2950 =   0.1145 +0,2993 = 0.4138

Frequency of red allele (R): 846 / 2950 + 0.2993 = 0.2867+ 0.2993 = 0.5830

question3.. expected no of blue flowers = 2950/4 = 737.5

question 4.. expected no. of violot plants = 1475

question 5.. expected no. of red plants = 737.5

question 6.. chi square values = (338 -737.5)2 / 737.5 + (1766 - 1475)2 / 1475 + (846 - 737.5)2 / 737.5

                                               = 216.407 + 57.411 + 15.962

                                               = 289.780

question 7.. degrees of freedom = (no. of rows-1) * (no. of columns -1) = (3-1)(2-1) = 2

question 8.. 5.991

question 10. we reject the hypothesis

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