Jamie just bought two boxes. The first box is square, which is side measuring 10

Question

Jamie just bought two boxes. The first box is square, which is side measuring 10 units,and is 4 units high. The second box is rectangular and has twice the volume of the square box. If the height of the second box is 5 units, and the width is 10 units, what is the length of the second box? Jamie just bought two boxes. The first box is square, which is side measuring 10 units,and is 4 units high. The second box is rectangular and has twice the volume of the square box. If the height of the second box is 5 units, and the width is 10 units, what is the length of the second box?

Explanation / Answer

Given that side(a) of first box is 10 and height(h) equal to 4. Hence the volume is V1=a*a*h=10*10*4=400.

Also given that volume of second box V2=2*V1. Height(h) is 5 and width(b) equal to 10.

Let 'l' be the length of the second box.

Now V2=l*b*h=l*10*5=50l.

We have that V2=2V1 which implies 50l=2*400.

Therefore, l=2*400/50 = 800/50 =16.

Hence, the length of second box is 16.

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