Let X be an exponential random variable with parameter and moment generating fun
ID: 3387531 • Letter: L
Question
Let X be an exponential random variable with parameter and moment generating function mX(t) = /( – t). Let random variable Y = 2X. Then the moment generating function of Y is
mY(t) = /( – 2t)
mY(t) = /(2 – t)
mY(t) = /( – t)2
mY(t) = 2/( – t)
Let X be an exponential random variable with parameter and moment generating function mX(t) = /( – t). Let random variable Y = 2X. Then the moment generating function of Y isA.
mY(t) = /( – 2t)
B. None of the given mgf’s. C.mY(t) = /(2 – t)
D.mY(t) = /( – t)2
E.mY(t) = 2/( – t)
Explanation / Answer
If X and Y have same distirbution then mX(t)=mY(t) in that situation the answer is (A).
Otherwise if answer (E) is correct
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