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Please help me break this down into steps. thank you An economist claims that av

ID: 3387190 • Letter: P

Question

Please help me break this down into steps. thank you

An economist claims that average weekly food expenditure of household in City 1 is more than that of household in City 2. She surveys 35 households in City 1 and obtains an average weekly food expenditure of $164.00. A sample of 30 households in City 2 yields an average weekly food expenditure of $159. Historical data reveals that the population standard deviation for City 1 and City 2 are $12.50 and $9.25, respectively. At the 5% significance level, is the economist claim supported by the data?

Explanation / Answer

Set Up Hypothesis
Null, City 1 is less than OR equal that of household in City 2 Ho: u1 <= u2
Alternate, City 1 is more than that of household in City 2 H1: u1 > u2
Test Statistic
X(Mean)=164
Standard Deviation(s.d1)=12.5
Number(n1)=35
Y(Mean)=159
Standard Deviation(s.d2)=9.25
Number(n2)=30
we use Test Statistic (Z) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
Zo=164-159/Sqrt((156.25/35)+(85.5625/30))
Zo =1.85
| Zo | =1.85
Critical Value
The Value of |Z | at LOS 0.05% is 1.645
We got |Zo | =1.849 & | Z | =1.645
Make Decision
Hence Value of | Zo | > | Z | and Here we Reject Ho
P-Value: Right Tail -Ha : ( P > 1.85 ) = 0.03226
Hence Value of P0.05 > 0.03226,Here we Reject Ho

we conclude that average weekly food expenditure of household in
City 1 is more than that of household in City 2

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