Please help me answer this question!! THANKS SO MUCH INADVANCE!! a) A sample of

Question

Please help me answer this question!! THANKS SO MUCH INADVANCE!!

a) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas.

b) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas.

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure.

Explanation / Answer

a) A sample of an ideal gas is at a temperature of 320 K. Therms molecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas.
rms velocity , u = (3RT/M ) Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol
b) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas. rms velocity , u = (3RT/M ) Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

                                                      = 3 * 10^-3 Kg / mol
b) A sample of an ideal gas is at a temperature of 320 K. The rmsmolecular speed at this temperature is measured as 1631 m/s.Calculate the mass of a molecule of this gas. rms velocity , u = (3RT/M ) Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

Given u = 1631 m / s Temperature , T = 320 K R = gas constant = 8.314 J/ mol . K Molar mass of the gas molecule , M = 3RT / u 2                                                       = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

                                                      = 3 * 10^-3 Kg / mol

c) The initial pressure in an ideal gas is 1.40 atm when itstemperature is 299 K. The temperature is increased to 315 K and thevolume is increased to 1.29 times its initial value. Calculate thefinal pressure From gas law PV = nRT PV / T = P' V' / T' P = 1.4 atm V ' = 1.29 V T = 299 K T' = 315 K P' = ? P' = PVT' / TV'     = 1.143 atm

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