1.) An April 2004 article on Hear The Issues.com stated that Americans have an a
ID: 3387125 • Letter: 1
Question
1.) An April 2004 article on Hear The Issues.com stated that Americans have an average of 2.24 televisions per household (source: Nielsen Media Research). If the standard deviation for the number of televisions in a U.S. household is 1.2 and a random sample of 80 American households is selected, the mean of this sample belongs to a sampling distribution.
2.)If the Confidence Level is 99%, the Confidence Coefficient for calculating the confidence interval for the mean is 2.33. T or F? Please show calculations as to why or why not.
Explanation / Answer
CI = x ± Z a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=2.24
Standard deviation( sd )=1.2
Sample Size(n)=80
Confidence Interval = [ 2.24 ± Z a/2 ( 1.2/ Sqrt ( 80) ) ]
= [ 2.24 - 2.58 * (0.134) , 2.24 + 2.58 * (0.134) ]
= [ 1.894,2.586 ]
ANS: FALSE
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