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Score: 0 of 1 pt 3 of 18 (0 complete) Hw Score: 0% 6.5.7-T Question reach distan

ID: 3374471 • Letter: S

Question

Score: 0 of 1 pt 3 of 18 (0 complete) Hw Score: 0% 6.5.7-T Question reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8 cm. The overhead a. Find the probability that an individual distance is greater than 210.00 cm. b. Find the probability that the mean for 25 randomly selected distances is greater than 198.70 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30? a. The probability is Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer Clear All parts

Explanation / Answer

mu= 200

sigma= 8

X= 210

Z=(X-mu)/sigma

=(210-200)/8

=1.25

Required probability = P(Z>1.25) ...........by using 1-NORM.S.DIST(1.25,TRUE)

= 0.10565

rounded answer is 0.1057

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