A car dealership has 77 ?red, 1313 ?silver, and 44 black cars on the lot. Ten ca
ID: 3371536 • Letter: A
Question
A car dealership has
77
?red,
1313
?silver, and
44
black cars on the lot. Ten cars are randomly chosen to be displayed in front of the dealership. Complete parts? (a) through? (c) below.
?(a) Find the probability that 4 cars are red and the rest are silver.
nothing
?(Round to four decimal places as? needed.)
?(b) Find the probability that
66
cars are red and
44
are black.
nothing
?(Round to six decimal places as? needed.)
?(c) Find the probability that exactly
77
cars are red.
nothing
?(Round to five decimal places as? needed.)
Explanation / Answer
a)
We have 7 red cars, 13 silver and 4 black cars
we need to select 4 cars from 7 red cars and rest of 6 cars from 13 silver cars
so number of ways = 7C4 * 13C6
= 35 * 1716
= 60060
total ways =selecting 10 cars out of total of 24 cars
this can be done in 24C10 ways =1961256
so P = 60060/1961256
= 0.0306
b)
we have to select 6 red cars out 7 red cars and 4 black cars out of 4 cars
this can be done in 7C6 * 4C4 ways
= 7 * 1
= 7
total ways =selecting 10 cars out of total of 24 cars
this can be done in 24C10 ways =1961256
so P = 7/1961256
= 0.000004
c)
we have to select 7 red cars out of 7 red cars and rest 3 cars out of rest of 17 cars
so number of ways = 7C7 * 17C3
= 1 * 680
= 680
so P = 680/1961256
= 0.00035
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