A car dealership has 8 red, 10 silver, and 3 black cars on the lot. Ten cars are

Question

A car dealership has 8 red, 10 silver, and 3 black cars on the lot. Ten cars are randomly chosen to be displayed in front of the dealership. Complete parts (a) through (c) below. (a) Find the probability that 4 cars are red and the rest are silver. nothing (Round to four decimal places as needed.) (b) Find the probability that 7 cars are red and 3 are black. nothing (Round to six decimal places as needed.) (c) Find the probability that exactly 8 cars are red. nothing (Round to five decimal places as needed.)

Explanation / Answer

Solution:-

(a) P(4 red AND 6 silver) = (8C4*10C6)/21C10

= (70*210)/352716

= 0.0417

(b) P(7 red AND 3 black) = (8C7*3C3)/21C10
= (8*1)/352716
= 0.000022

(c) P(8 red AND 2 other) = (8C8*13C2)/21C10
= (1*78)/352716
= 0.00022

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