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ith their root. It Americans are randomly selected, how many Uliets in public t)

ID: 3371112 • Letter: I

Question

ith their root. It Americans are randomly selected, how many Uliets in public t) Co sin ex (g) C e tf 500 adult Americans expect to flush toilets in public restrooms with would we b) Woul Bor? b ush toilets in public restrooms with their foot? their foot? uld it be unusual to observe 280 adult Americans who Would it b ergy Sufferers Clarinex-D is a medication whose purpose 6. Aller duce the symptoms associated with a variety of allergies. is to experienced insomnia as a side effect. (a) If 240 users of Clarinex-D are randomly selected, how many to re in clinical trials of Clarinex-D, 5% of the patients in the study would we expect to experience insomnia as a side effect? b) Would it be unusual to observe 20 patients experiencing insomnia as a side effect in 240 trials of the probability experiment? Why? 47, Spanking In March 1995, The Harris Poll reported that 80% of parents spank their children. Suppose a recent poll of 1030 adult Americans with children finds that 781 indicated that

Explanation / Answer

Q46

Let X = Number of Clarinex-D using patients experiencing insomnia as a side effect.

Then, X ~ B(n, p), ………………………………………………………………………(1) where p = sample size and p = probability of Clarinex-D using patients experiencing insomnia as a side effect, which is also equal to the proportion of Clarinex-D using patients experiencing insomnia as a side effect.

Given 5% of patients in the study experienced insomnia as a side effect, p = 0.05 …….. (2)

Back-up Theory

If X ~ B(n, p). i.e., X has Binomial Distribution with parameters n and p, where n = number of trials and p = probability of one success, then probability mass function (pmf) of X is given by p(x) = P(X = x) = (nCx)(px)(1 - p)n – x, x = 0, 1, 2, ……. , n …………………..(1)

[The above probability can also be directly obtained using Excel Function of Binomial Distribution: BINOMDIST(Number_s:Trials:Probability_s:Cumulative), what is within brackets is (x:n:p:True)] ………………………………………………………………….(1a)

Mean (average) of X = E(X) = np………………………………………………..(2)

Now to work outthe solution:

Part (a)

Expected number of patients experiencing insomnia as a side effect in a sample of 240

= E(X), where X ~ B(240, 0.05)

= 240 x 0.05 [vide (2)]

= 12 ANSWER

Part (b)

To answer this part, probability of finding 20 patients experiencing insomnia as a side effect in a sample of 240

= P(X = 20)

= 0.0088 [1a]

Since the above probability is very low, it is reasonable to assume that it is unusual to observe 20 patients experiencing insomnia as a side effect in a sample of 240. ANSWER