his Question: 10 pts Time Limit: 01.00.00 Submit Quiz 10 of 10 (0 complete) This
ID: 3370722 • Letter: H
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his Question: 10 pts Time Limit: 01.00.00 Submit Quiz 10 of 10 (0 complete) This Quiz: 100 pls possible The weights of a certain brand of candies are normally distributed with a mean weight of 0.8618 g and a standard deviation of 0 051g A sample of these candes came from a package containing 451 candies, and the package label stated that the net weight is 3852g (f every package has 451 candies, the mecan weight of the candes 385.2 must exceed0.8542 g for the net contents to weigh at least 385 2g) a. If 1 candy is randomly selected, find the probability that it weighs more than 0.8542 g The probability is (Round to four decimal places as needed.) b. If 451 candies are randomly selected, find the probability that their mean weight is at least 0 8542 g The probability that a sample of 451 candies will have a mean of 0 8542 g or greater is Round to four decimal places as needed) c. Given these results, does it seem that the candy company is providing consumers with the amount claimed on the label? Y because the probability of getting a sample mean of 0 8542 g or greater when 451 candies are selectedexcetonall a Enter your answer in each of the answer boxes 02Explanation / Answer
Solution:- Given mean = 0.8618, standard deviation = 0.051
a) P(x > 0.8542) = P((x-?)/? > (0.8542 - 0.8618)/0.051)
= P(Z > -0.1490)
= 0.5596
b) For n = 451
P(x > 0.8542) = P((x-?)/(?/sqrt(n) > (0.8542 - 0.8618)/(0.051/sqrt(451))
= P(Z > -3.1647)
= 0.9992
c) YES because the probability of getting a sample mean of 0.8542g or greater when 451 candies are selected IS NOT exceptionally small
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