e. Using 50 random numbers given below, compute the mean and standard deviation.

Question

e. Using 50 random numbers given below, compute the mean and standard deviation. 0.924527 0.291694 0.949087 0.235243 0.491214 0.971717 0.911938 0.709438 0.784626 0.834357 0.308613 0.139508 0.921094 0.769815 0.008079 0.316744 0.636747 0.666959 0.897957 0.755709 0.498843 0.702352 0.956940 0.699935 0.951105 0.194260 0.982627 0.413472 0.174505 0.967928 0.089648 0.460031 0.051266 0.222969 0.405808 0.848295 0.457351 0.300964 0.380064 0.331327 0.413537 0.446078 0.604987 0.932309 0.571094 0.697508 0.809287 0.950670 0.870501 0.743559 Mean (to 6 decimals) Standard deviation (to 6 decimals)

Explanation / Answer

Using R we can have,

CODE:

x <- c(0.924527,0.291694,0.949087,0.235243,0.491214,0.971717,0.911938,0.709438,0.784626,0.834357,0.308613,0.139508,0.921094,0.769815,0.008079,0.316744,0.636747,0.666959,0.897957,0.755709,0.498843,0.702352,0.956940,0.699935,0.951105,0.194260,0.982627,0.413472,0.174505,0.967928,0.089648,0.460031,0.051266,0.222969,0.405808,0.848295,0.457351,0.300964,0.380064,0.331327,0.413537,0.446078,0.604987,0.932309,0.571094,0.697508,0.809287,0.950670,0.870501,0.743559)
mean(x)
sd(x)

OUTPUT:

> x <- c(0.924527,0.291694,0.949087,0.235243,0.491214,0.971717,0.911938,0.709438,0.784626,0.834357,0.308613,0.139508,0.921094,0.769815,0.008079,0.316744,0.636747,0.666959,0.897957,0.755709,0.498843,0.702352,0.956940,0.699935,0.951105,0.194260,0.982627,0.413472,0.174505,0.967928,0.089648,0.460031,0.051266,0.222969,0.405808,0.848295,0.457351,0.300964,0.380064,0.331327,0.413537,0.446078,0.604987,0.932309,0.571094,0.697508,0.809287,0.950670,0.870501,0.743559)
> mean(x)
[1] 0.5930857
> sd(x)
[1] 0.2933262

So, the mean is 0.593086 and sd is 0.293326 [rounding to 6 decimal places].

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