#1. A new San Bernardino Bakery created two online ads for their signature San B
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Question
#1.
A new San Bernardino Bakery created two online ads for their signature San Berryminto Cake, one with a person in it, and one without.
They want to know if having the person in the ad can predict their total revenue they receive from online orders.
The ADMN 210 intern in charge of the analysis used ?=0.01.
A. Not enough information, must personally try the cake first.
B. Cake ad design can significantly predict revenue. Customers who viewed the person with the cake spent $89 more than the ad without the cake, on average.
C. Customers who viewed the person with the cake spent $9.96 less than the ad without the cake, on average. However, this could NOT significantly predict the revenue.
D. Cake ad design can significantly predict revenue. For everyone 1 customers who viewed the person with the cake, they spent $9.96 additional on average.
#2 What is true about the scatterplot below? For the slope of foundation condition, p=0.0001 and ?=0.05
a.here is a negative correlation between foundation condition and innovative capacity.
b.For every 1 unit increase in foundation condition, innovative capacity increases by 0.5349 units.
c. No significant correlation.
d. The slope of the line (coefficient for foundation condition) is 43.5
#3.
An independent-samples t-test showed that there was a significant difference in mean # of donut holes eaten between group A and B (p-value was less than 0.05). The average # of donut holes eaten was 20 in group A and 30 in group B. The average difference (30-20=10) can be thought of as the practical significance.
a. True
b. False
Explanation / Answer
For part 1 you need to provide the data like sample means for the two groups, their corresponding variances, and scatter plot for part 2.
(3)
It is given that p-value is less than 0.0, which means that the null hypothesis is rejected.
Now, p-value is calculated from test statistic value.
Assuming that z-test statistic is used. The formula is:
z = (30-20)/SE, here SE is the standard error.
Hence we see that standard error is the main factor which contributes to the z-value, from which the corresponding p-value is calculated.
So only the average difference can not be thought of as the practical significance, and standard error must also be taken into account.
So the answer is False.
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