1. There are 137 orange M&M\'s in a bowl. Find the probability of selecting an M

Question

1. There are 137 orange M&M's in a bowl. Find the probability of selecting an M&M that is not orange from the bowl that has 692 M&M's in it. Convert your answer to decimal form to the nearest thousandth.

2. Find the z score value for a score of 92 with respect to a sample of exam grades that have a mean score of 75.9 and a standard deviation of 11.1.

3. A box contains nine red, five yellow, and six green lenses. One lens is randomly selected from the box. Find the probability that the selected lens is yellow or green.

Explanation / Answer

#1.
There are total 692 M&M's in a bowl. And out of this 137 are orange.
Hence 692 - 137 = 555 are not orange

Hence, P(Not orange) = 555/692 = 0.8020

#2.
Using central limit theorem,
z = (xbar - mu)/sigma
z = (92 - 75.9)/11.1
z = 1.4505

#3.
9 - Red, 5 - Yellow, 6 - Green
total = 20 lenses

Required probability = (9 + 5)/20 = 0.7

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