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1. The vernier caliper reads____cm 2. T he main idea in lab today is that a subm

ID: 2263854 • Letter: 1

Question

1. The vernier caliper reads____cm


2. The main idea in lab today is that a submerged object is buoyed up by a force which depends on its

a). density

b)volume

c)weight

d)mass


3. A rock has a volume of 6.68x10-6 m3. When it is completely submerged in a beaker of water, the water exerts a buoyant force on the rock equal to ____newtons


4. A right circular cylinder has a radius of 2.50 cm and a length of 30.8 cm. Its volume is___cm^3


5. A piece of material has a mass of 3.16 kg and a volume of 279 cm3. The material is most likely

a) gold

b)lead

c)iron

d)mercury




The vernier caliper reads a distance of 3.80 cm. 4.07 cm. 3.17 cm. 3.71 cm.

Explanation / Answer

Q1..

The "zero" of vernier scale is after 3.1 .... so main scale reading is 3.1

also the 7th division of vernoer coincides with main scale ... so vernier scale reading = 0.07

so ... total reading = 3.17 cm ... option c


Q2 ..

Buoyant force = volume_of_body * density_of_liquid * acc due to gravity..

so option b) volume



Q3

buoyant force = volume * density of water * 9.8 = 6.68 * 10^-6 * 1000 * 9.8 = 0.065464 N


Q4

volume = pi * radius^2 * heigth = pi * 2.5^2 *30.8 = 604.7565 cm^3


Q5

density of material = mass / volume = 3160 grams / 279 = 11.326 g/cm^3

density of gold = 19.32 g/cm3
density of lead = 11.34
desntiy of iron = 7.87
density of mercury = 13.6


so option b) lead