Use the information in the following table for the next few questions. The follo

Question

Use the information in the following table for the next few questions. The following statistics represent samples of copper wire submitted by two companies for tensile strength testing (psi).

Statistic                                                      Company A        Company B

Arithmetic Mean                                       500                     600

Median                                                     500                      500

Mode                                                       500                     300

Standard Deviation                             40                        20

Mean Absolute Deviation                         32                      16

Quartile Deviation                                     25                         14

Range                                                       240                       120

Sample Size                                          100                           80

The middle 50 percent of the wires of Company A tested between _____ and _____?

Explanation / Answer

Ans:

For company A:

Quartile deviation=(Q3-Q1)/2=25

Also,

median=500

As,mean,median and mode is same for company A,it means distribution of tensile strength is normally distributed.

So,midddle 50% will be between 500-25=475 and 500+25=525

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