4. [4] In a report on why e-shoppers abandon their online sale transactions, a s

Question

4. [4] In a report on why e-shoppers abandon their online sale transactions, a study found that "pages took me too much time to load" and "site was too confusing to me so that I couldn't find the product were the two main complaints heard most often. Based on 50 customers responses, the average time to complete online order was 5.3 minutes and the standard deviation was 3.1 minutes. Construct a 95% confidence interval for the average completion time for an online order 5, [4] In a poll of n = 700 randomly selected adults, 390 indicated that movies are getting better. Construct a 90% confidence interval for the overall proportion p of adults who say that movies are getting better.

Explanation / Answer

1) xbar= 5.3 and sigma=3.1 and n=50

95% CONFIDENCE INTERVAL OF POPULATION MEAN

xbar = 5.3
ZCRITICAL = 1.96
sM = (3.12/50) = 0.44
= xbar ± Z(sM)
= 5.3 ± 1.96*0.44
= 5.3 ± 0.859

95% CI [4.441, 6.159].

You can be 95% confident that the population mean () falls between 4.441 and 6.159.

2) n= 700 x=390 and p= 390/700= 0.5571 = q=1-0.5571=0.4429

90%confidence interval

Lower bound = P - (Z*SEM) = 0.526

0.5571-1.645*0.01877= 0.526

Upper bound = P + (Z*SEM)

0.5571+1.645*0.01877 = 0.588

You can be 90% confident that the population p falls between 0.526 and 0.588

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