A manufacturer of disk drives for notebook computers wants a MTBF of at least 50

Question

A manufacturer of disk drives for notebook computers wants a MTBF of at least 50,000hours. Recent test results for 15 units were two failures at 12,000?hours,

one at 20,000 ?hours, and one more at 40,000 hours. The remaining units were still running at 60,000 hours.

Determine the? following:

?b) Number of failures per? unit-hour =

?c) The mean time between failures? (MTBF) is the expected time between a repair and the next failure of a? component, machine,?process, or product. MTBF is the reciprocal of? FR(N):

MTBF at this time in testing? = (round your response to the nearest whole? number).

Explanation / Answer

There are total of 4 failures in calculated time duration of 60,000 hours

Therefore , number of failures per unit – hour = 4/ 60000 = 0.000066

Mean time between failure

= 60,000 hours/ 4 failures

= 15,000 hours

NUMBER OF FAILURES PER UNIT HOUR = 0.000066

MEAN TIME BETWEEN FAILURE = 15,000 HOURS

NUMBER OF FAILURES PER UNIT HOUR = 0.000066

MEAN TIME BETWEEN FAILURE = 15,000 HOURS

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