.> C | www.webassign.net/web/Student/Assignment-Responses/submit?dep:17481 399 :

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.> C | www.webassign.net/web/Student/Assignment-Responses/submit?dep:17481 399 : Apps D Registration Holds control Panel in Wir BookmarksPhysics-BUS 1120 C 9 How Do l Change M -derivative Nelnet Campus Com EZTV TV Torrents 0 In this problem, assume that the distribution of differences is approximately normal. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smalfer. In some situations, this choice of d.f. may increase the P-value by a small amount and therefore produce a slightly more "conservative" answer. At five weather stations on Trail Ridge Road in Rocky Mountain National Park, the peak wind gusts (in miles per hour) for January and April are recorded below Weather station Janu 126 64 78 4 88 6 Does this information indicate that the peak wind gusts are higher in January than in April? Use = 0.01. (Let d-January-April.) (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? 0; two-tailed Ho: ,-0; H1 : Ho: Ho: ,-0; H1' . 0; right-tailed > 0; H1 : ,-0; right-tailed O @ (b) What sampling distribution will you use? What assumptions are you making? O The standard normal. We assume that d has an approximately uniform distribution. The Student's t. We assume that d has an approximately normal distribution. The standard normal. We assume that d has an approximately normal distribution. The Student's t. We assume that d has an approximately uniform distribution. What is the value of the sample test statistic? (Round your answer to three decimal places.) (c) Find (or estimate) the p-value. (Round your answer to four dedimal places.) Sketch the sampling distribution and show the area corresponding to the P-value. ENG 10:14 AM Desktop ^ US 1/9/20174

Explanation / Answer

(a) Level of significance = 0.01

Null Hypothesis : H0 : d = 0

Ha : d  > 0 Right tailed

OPtion D is correct.

(b) We willl use t- distribution as it is appxomiately normal. Option B is correct.

(c) Here the difference table is give below

Here dbar = 9.8

standard deviation of differnce sd = 22.0159

standard error of difference se0 = sd / sqrt(n) = 22.0159/ sqrt(5) = 9.846

so test stastic

t = dbar /se0 = 9.8/ 9.846 = 0.995

Estimate p value= 0.1880

here the sketch option (c) is correct .

(d) at the alpha level 0.01 , we fail to reject the null hypothesis and conclude that data are not statistically significant. Option C is correct.

WS January April Diffeence 1 126 115 11 2 139 102 37 3 122 114 8 4 64 88 -24 5 78 61 17 average 9.8 std.dev. 22.0159

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