Explain if the data is not normally distributed, will the result from part a and

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Explain if the data is not normally distributed, will the result from part a and b valid.
Question. The orange juice company advertised that can of orange juice contains 400mL. In fact, the amount of product in can is normally distributed with a mean of 400.6 mL and standard deviation of 1mL. Part a asks the probability that a randomly selected can contain less than 400mL. Part b asks the probability that 50 randomly selected cans contain less than 400mL.
My question is if the data is not normally distributed, will the result from part a and b valid. Why? Explain if the data is not normally distributed, will the result from part a and b valid.
Question. The orange juice company advertised that can of orange juice contains 400mL. In fact, the amount of product in can is normally distributed with a mean of 400.6 mL and standard deviation of 1mL. Part a asks the probability that a randomly selected can contain less than 400mL. Part b asks the probability that 50 randomly selected cans contain less than 400mL.
My question is if the data is not normally distributed, will the result from part a and b valid. Why?
Question. The orange juice company advertised that can of orange juice contains 400mL. In fact, the amount of product in can is normally distributed with a mean of 400.6 mL and standard deviation of 1mL. Part a asks the probability that a randomly selected can contain less than 400mL. Part b asks the probability that 50 randomly selected cans contain less than 400mL.
My question is if the data is not normally distributed, will the result from part a and b valid. Why?

Explanation / Answer

a)

P(X < 400) = P(Z < 400-400.6/1)

= P(Z < 0.6)

=0.7257

b) P(X <400) = P(Z < 400-400.6/sqrt(50))

= P(Z < 4.243)

= 1

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