Work is appreciated. Worksheet 10: MEDIANS FROM FREQUENCY DISTRIBUTIONS RIDDLE:

Question

Work is appreciated.

Worksheet 10: MEDIANS FROM FREQUENCY DISTRIBUTIONS

RIDDLE: Why did the muffler repair person quit her job?

Directions: To find the answer to the riddle, write the answers to the problems on the lines. The word in the solution section beside the answer to the first problem is the first word in the answer to the riddle, the word beside the answer to the second problem is the second word, and so on. Round your answers to two decimal places.

Group A

Group B

Group C

Group D

Group E

Group F

What is the median of Group A's scores? _____

What is the median of Group B's scores? _____

What is the median of Group C's scores? _____

What is the median of Group D's scores? _____

What is the median of Group E's scores? _____

What is the median of Group F's scores? _____

Solution Section:

20.50 (HOME) 17.85 (PAY) 17.35 (SHE) 98.02 (WORKS)
5 7.49 (FEELING) 56.83 (AUTOMOBILES) 51.40 (EXHAUSTED)
49.88 (REPAIRS) 97.98 (ALWAYS) 7.21 (EMPLOYMENT)
596.71 (WENT) 18.5 (APPLICATION) 50.12 (DISCRIMINATION)

Write the answer to the riddle here, putting one word on each line:
__________ __________ __________ __________ __________
__________

Explanation / Answer

Group A:

There are 33 data values (sum of frequency) is set A.

So median will be 17th data value. Since 17th data value is 17.

So median of Group A's scores is 17.

Group B:

There are 221 data values (sum of frequency) is set B.

So median will be 111th data value. Since 111th data value is 98.

So median of Group B's scores is 98.

Group C:

There are 21 data values (sum of frequency) is set C.

So median will be 11th data value. Since 11th data value is 597.

So median of Group C's scores is 597.

Group D:

There are 64 data values (sum of frequency) is set D.

So median will be average of 32nd and 33rd data values. Since 32nd data value lie in interval 18-20 and 33rd both data values lies in the interval 21-23 so median will be

(23+18)/2=20.5

So median of Group D's scores is 20.5.

Group E:

There are 247 data values (sum of frequency) is set E.

So median will be 124th data value. Since 124th data value lies in interval 57-59 so median will be

(57+59)/2=58

So median of Group E's scores is 58.

Group F:

There are 120 data values (sum of frequency) is set F.

So median will be average of 60th and 61st data values. Since 60th and 61st data values lie in the interval 50-54 so median will be

(50+54)/2=52

So median of Group E's scores is 52.

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