eSchool Solutions De Homework-LUNIOUE IEROME Google Chome QMB3200 Fal 2017 U13 R
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Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: 1 - 2 = 0
Alternative hypothesis: 1 - 2 0
Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the difference between sample means is too big or if it is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.10. Using sample data, we will conduct a two-sample t-test of the null hypothesis.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = sqrt[(s12/n1) + (s22/n2)]
SE = 12.05
D.F = 70
t = [ (x1 - x2) - d ] / SE
t = 2.35
tcritical = 1.667
Rejection region is t > 1.667
where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is the size of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between the population means, and SE is the standard error.
Since we have a two-tailed test, the P-value is the probability that a t statistic having 40 degrees of freedom is more extreme than - 2.35; that is, less than -2.35 or greater than 2.35.
Thus, the P-value = 0.022
Interpret results. Since the P-value (0.022) is less than the significance level (0.10), we cannot accept the null hypothesis.
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