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My N Suppose we have a binomial experiment in which success is defined to be a p

ID: 3361116 • Letter: M

Question

My N Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us. (a) Suppose n-38 and p-0.20. Can we approximate by a normal distribution? why? (Use 2 decimal places.) nq= Select 7pSelect 7be approximated by a normal random varlable because Select What are lhe values ol 0 and a? Use 3 decimal places.) (b) Suppose n-75 and = 0.15. Can we safely approximate hy a normal distribution? why or why not Select Select be approxlmated by a normal random varlable because Sele. (c) Suppose n-45 and -0.34. Can we approximate p by a normal distribution? why? (Use 2 decimal places.) -Select . ' p -Select- be approximated by a normal random variable because What are the values of Hig and 7 (Use 3 decimal places.) Need Help?eadTalk to a Tutor 22 points | Previcus Answes EBBasiS.at7 7.R.014 My N Find z such that 57% of the standard normal curve lies between 2 and Z (Round your answer to two decimal places. 79 Need Help? Talk to Submt Answer ave PragressPracce Another Version -/2 points BBBasicstat77. R.015. My Notes Blcod typc AB is found in only 3% of the populationt. If 155 pcople are chosen at random, find the probability of the following (Usethe normal approximation, Round your answers to four decimal places.)

Explanation / Answer

Solution:-
a) Give that n = 38, p =0.20

np = 38*0.20 = 7.60

nq = 38*0.80 = 30.40
  
np > 5 and nq > 5.

Yes, p^ can be approximated by a normal random variable because np and nq exceed = 5

=> = np = 7.600

=> = sqrt(npq) = 2.466

b) n = 25 p = 0.15

np = 25*0.15 = 3.75 < 5

nq = 25*0.85 = 21.25 > 5

No, p^ cannot be approximated by a normal random variable because np does not exceed = 5

c) Give that n = 45, p =0.34

np = 45*0.34 = 15.30

nq = 45*0.66 = 29.70
  
np > 5 and nq > 5.

Yes, p^ can be approximated by a normal random variable because np and nq exceed = 5

=> np = 15.300

=> sqrt(npq) = 3.178

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