The mean daily production of a herd of cows is assumed to be normally distribute

Question

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 38 liters, and standard deviation of 2.8 liters.

A) What is the probability that daily production is less than 37.2 liters? Use technology (not tables) to get your probability.

Answer= (Round your answer to 4 decimal places.)

B) What is the probability that daily production is more than 45.5 liters? Use technology (not tables) to get your probability.

Answer= (Round your answer to 4 decimal places.)

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 38 liters, and standard deviation of 2.8 liters A) What is the probability that daily production is less than 37.2 liters? Use technology (not tables) to get your probability. Answer- B) What is the probability that daily production is more than 45.5 liters? Use technology (not tables) to get your probability Answer- Round your answer to 4 decimal places.) (Round your answer to 4 decimal places.)

Explanation / Answer

= 38 = 2.8

A) Using R studio

> pnorm(37.2,38,2.8)
[1] 0.3875485

= 0.3876

B) Using R studio

> pnorm(45.5,38,2.8,lower.tail=FALSE)
[1] 0.003696848

= 0.0037.

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