J r. Scientist has developed a compound that he suspects can ffect the height of
ID: 3359158 • Letter: J
Question
J r. Scientist has developed a compound that he suspects can ffect the height of a growing individual. In order to test ypothesis, he injected the sane dosage of the compound to each of the 40 growing guinea pigs in his treatsent" group injected nothing to each of the other 90 growing guinea pigs In his "control increase in body iength in each of these treated/untrea growing guinea pigs. The following is his results: he measured the ted 130 Then, after six months, Treatnent group (sanple size is 40)1 Sample mean increase in body 1ength is 1.40 inches Sample standard deviation is 0.20 inch Sanple variance is o.04 inch Control group (sample size is 90) Sanple mean increase in body length is 1.30 inches Sample standard deviation is 0.30 ineh Sample variance is 0.09 inch Use a significance level of o.o the against the alternative hypothesis that the increases in body length of the two infornation, the calculated s, test the null hypothesis that increases in body length of the two groups are the sane groups are not the sane. Based on these is (x1-X2) A. 2.26 . 3236 C 5. 00 B. -2.236 C. +50.000 D. Not enough infornation given to answer this question E. None of the above Please continue on the next pageExplanation / Answer
8.
Given that,
mean(x)=1.4
standard deviation , 1 =0.2
number(n1)=40
y(mean)=1.3
standard deviation, 2 =0.3
number(n2)=90
null, Ho: u1 = u2
alternate, H1: 1 > u2
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.645
since our test is right-tailed
reject Ho, if zo > 1.645
we use test statistic (z) = (x-y)/sqrt(s.d1^2/n1)+(s.d2^2/n2)
zo=1.4-1.3/sqrt((0.04/40)+(0.09/90))
zo =2.2361
| zo | =2.2361
critical value
the value of |z | at los 0.05% is 1.645
we got |zo | =2.236 & | z | =1.645
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail -Ha : ( p > 2.2361 ) = 0.01267
hence value of p0.05 > 0.01267,here we reject Ho
ANSWERS
---------------
null, Ho: u1 = u2
alternate, H1: 1 > u2
a.
test statistic: 2.236
critical value: 1.645
decision: reject Ho
p-value: 0.01267
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