J (b) work done on the box by the force of gravity J (c) work done on the box by

Question

J

(b) work done on the box by the force of gravity
J

(c) work done on the box by the normal force
J

(d) increase in gravitational potential energy of the box as it moves up the wall
J

A force of constant magnitude pushes a box up a vertical surface as shown in the figure. The box moves at a constant speed. If the mass of the box is 6.70 kg, it is pushed 2.40 m vertically upward, the coefficient of friction is 0.350 and the angle (a) work done on the box by F theta is 30.0 determine the following. (b) work done on the box by the force of gravity (c) work done on the box by the normal force (d) increase in gravitational potential energy of the box as it moves up the wall

Explanation / Answer

N = F*cos30

f = u*N = u * F * cos30

Fy net = 0

F*sin30 - mg - f = 0

F*sin30 - mg - u * F * cos30 = 0

F = (m*g)/(sin30 + u*cos30)

F = 82 N

a) W_F = Fy*y = F*sin30 * y = 98.4 J

b) Wg = - m*g*y = -157.584 J

c) Wn = Fx * y *cos90 = 0

d) dU = 157.584 J

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