4. Use the following contingency table to determine whether variable 1 is indepe

Question

4. Use the following contingency table to determine whether variable 1 is independent of variable 2. Let =0.05. Variable 2 23 17 Total 21 20 18 8 Variable 1 Total Freq: Count Contingency Table Variable 1 By Variable 2 Count Expected Cell Chi 2 Z Total 12 23 21 11.0365 20.8467 24.1168 00841 0.2224 0.4028 45 20 8.86861 16.7518 19.3796 0.0851 00037 0.0199 17 18 7.09489 13.4015 15.5036 0.0013 04303 0.4020 36 27 5 5159 137 Total Tests DF -Loglike RSquare (U) 0.0058 137 4 0.83571979 Test Likelihood Ratio Pearson ChiSquare Prob> ChiSq 0.7959 0.7995 1.671 1652

Explanation / Answer

Ok. The chisquare test for independence has already been performed.

Now, Lets check the p-value of the test to determine if the variables are independent or not.

The p-value is .7959 , which means a value above .05. A value of .05 means that there is not eveidence that the variables are dependent on each other.

Hence, we conclude that the 2 variables are independent of each other

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