The data show chest size and weight of several bears. Find the regression equati

Question

The data show chest size and weight of several bears. Find the regression equation, letting the first variable be the independent (x) variable. Then find the predicted weight of a bear with a chest size of 50 inches. Is the result close to the actual weight of 337pounds? Use a significance level of 0.05.

Chest size (inches) 49 51 53 61 57 45 Weight (pounds) 368 382 420 481 457 287 What is the regression equation? y = ____ + _____x. Round to two decimal places as needed. What is the best predicted value? ______pounds. Round to one decimal place as needed.

Explanation / Answer

Ans:

Regression Equation(y) = a + bx

Slope(b) = (NXY - (X)(Y)) / (NX2 - (X)2)

Intercept(a) = (Y - b(X)) / N

Regression eqn:

y=11.89x-227.14

when x=50

y=11.89*50-227.14=367.4

x y xy x^2 y^2 1 49 368 18032 2401 135424 2 51 382 19482 2601 145924 3 53 420 22260 2809 176400 4 61 481 29341 3721 231361 5 57 457 26049 3249 208849 6 45 287 12915 2025 82369 Total 316 2395 128079 16806 980327

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