The percent of fat calories that a person in America consumes each day is normal

Question

The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 38 and a standard deviation of about 9. Suppose that 16 individuals are randomly chosen. Let X = average percent of fat calories consumed for a sample of size 16 . Enter numbers as integers or fractions in "p/q" form, or as decimals accurate to nearest 0.01 a. (.20) X ~ (pick one) (.20) Use the mean and standard deviation of X to determine the z value for X = 40 c (.20) llustrate P(X

Explanation / Answer

Solution:-
a) x ~ N (38,9/sqrt16)

b) z = ((40-38)/(9/sqrt16)) = 2/2.25 = 0.8888

c) fill left

d) P(x < 40) = P(Z < 0.8888) = 0.8133

e)P25 = 38 + (-0.6745)(9/sqrt16) = 38+(-0.6745*2.25) = 38 - 1.5176 = 36.4824

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