Homework: U2 HW 8: Section 12.2 (Hypothesis Test for 1 Popul Score: 0 72 of 1 pt
ID: 3356254 • Letter: H
Question
Homework: U2 HW 8: Section 12.2 (Hypothesis Test for 1 Popul Score: 0 72 of 1 pt 4 of 8 (8 complete) 12.2.81 The number of successes and the sample size for a simple random sample from a population are given below a. Determine the sample proportion b. Decide whether using the one-proportion z-test is appropriate c. If appropriate, use the one-proportion z-test to perform the specified hypothesis test The one proportion z-test is not appropriate Identify the critical value(s), if appropriate Select the correct choice below andif necessary, in the answer box to complete your answer , 2- (Round to two decimal places as needed ) Round to tiro decimal paces as needed ) 2 233 Round to two deckmal places as needed ) The one propertion z sest is not appropriate Nhat is the conclusion of the hypothesis test? Do not reject Ho the data do not provide sufficent evidence to concide that p >o 2 All parts showingExplanation / Answer
Given that,
possibile chances (x)=8
sample size(n)=32
success rate ( p )= x/n = 0.25
success probability,( po )=0.2
failure probability,( qo) = 0.8
null, Ho:p=0.2
alternate, H1: p>0.2
level of significance, = 0.01
from standard normal table,right tailed z /2 =2.33
since our test is right-tailed
reject Ho, if zo > 2.33
we use test statistic z proportion = p-po/sqrt(poqo/n)
zo=0.25-0.2/(sqrt(0.16)/32)
zo =0.7071
| zo | =0.7071
critical value
the value of |z | at los 0.01% is 2.33
we got |zo| =0.707 & | z | =2.33
make decision
hence value of |zo | < | z | and here we do not reject Ho
p-value: right tail - Ha : ( p > 0.70711 ) = 0.23975
hence value of p0.01 < 0.23975,here we do not reject Ho
ANSWERS
---------------
null, Ho:p=0.2
alternate, H1: p>0.2
test statistic: 0.7071
critical value: 2.33
decision: do not reject Ho
p-value: 0.23975
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