Homework: Section 3.3 Homework Score: 0 of 1 pt 3.3.14 Sav 30f 10 (2 complete) H

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Homework: Section 3.3 Homework Score: 0 of 1 pt 3.3.14 Sav 30f 10 (2 complete) HW Score: 20%, 2 of 10p Question Help I Listed below are the amounts of mercury (in parts per million, or ppm) found in tuna for the set of data. What would be the values of the measures of sushi sampled at different stores. Find the range, variance, and deviation variation if the tuna sushi contained no mercury? 0.97 0.86 1.13 0.39 0.97 0.77 0.27 es The range of the sample data is 0 860 ppm, Round to three decimal places as needed) es Sample variance ppm2 Round to three decimal places as needed ) gnm ocume Enter your ansver in the answer box and then cick Check Answe 2 Peraning

Explanation / Answer

Ans:

Range=1.13-0.27=0.86

Sample variance=0.612/6=0.102

Sample standard deviation=sqrt(0.102)=0.319

xi (xi-0.7657)^2 1 0.97 0.042 2 0.86 0.009 3 1.13 0.133 4 0.39 0.141 5 0.97 0.042 6 0.77 0.000 7 0.27 0.246 sum= 5.36 0.612 average= 0.7657 0.102 Range 0.86

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