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ID: 3356025 • Letter: #

Question

_ c secure https://drive.google.com/file/d/0B3KIAPYPrsKzUzLyMINILDZsODg/view ::: Apps a Amazon.co : Onlinr Online AlarmCinrk y Twittrr N %hone owuTube %Canas Ciration Machine:M MYahn Fin nre Rus tels F rgn SignOn· 10W rdr he Fss nti ther tkmars 12. Consider two events: A and B Open with a) P (A or B) is always equal to P b) P (A or B) is equal to P (A and B) only when A and B are independent has c) P(A or B) is equal to P (A and B only when A and B are not independent d) None of the ahove A survey is conducted in a metropolitan area. Households are asked if they use online streaming services

Explanation / Answer

12) Answer is option (d) none of the above as P(A or B) = P(A)+P(B)-P(A)P(B) (if A and B are independent)

13) Let Use of online streaming = O and use of Cable = C

P(no online streaming and no cable) = 1- P(O or C)

= 1-(P(O)+P(C)-P(O and C)) = 1 - 0.35-0.4+0.25 = 50%

So answer is option (b) About 50%

14) P(no O given that given that no C) = P(no O and no C)/P(no C)

= 0.5/0.0.6 = 0.8333

answer is (e) about 80%

15) P(disease is present given that test has given a positive result) = P(disease is present and test is positive)/P(positive result)

= (0.9*0.03)/(0.9*0.03+0.97*0.02)

= 0.582

so about 60%